Below is the python code to check if a given number is an Armstrong number or not
If a 3 digit number is equal to the sum of the cubes of its each digit, then it is an Armstrong Number.
num=int(input("Enter a 3 digit number:"))
summ=0
temp=num
while (temp>0):
digit=temp%10
summ+=digit**3
temp//=10
if (num==summ):
print(num,"is an Armstrong number")
else:
print(num,"is not an Armstrong number")
Output
Enter a 3 digit number:456
456 is not an Armstrong number