Leap Year in Python using Function

Learn about Leap Year in Python using Function in the below code example. Also, refer to the comments in the code snippet to get a detailed view about what’s actually happening.

Leap Year in Python using Function

The below program checks whether the year is a leap year or not using the function.

# Python program to check year is a leap year or not using function

#user-defined function
def checkYear(year):   
    # check leap year or not
    if (year % 4) == 0:
        if (year % 100) == 0:
            if (year % 400) == 0:
                return True
            else:
                return False
        else:
             return True
    else:
        return False

# year input
year = int(input('Enter a year: '))

# function call
if(checkYear(year)):
    print('{0} is a leap year'.format(year))
else:
    print('{0} is not a leap year'.format(year))

Output:

Enter a year: 1996
1996 is a leap year

Hope above code works for you and Refer the below Related Codes to gain more insights. Happy coding and come back again.

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