Learn about Sum of squares of N natural numbers in C using formula in the below code example. Also refer the comments in the code snippet to get a detailed view about what’s actually happening.
Contents
Sum of squares of N natural numbers in C without using loop
Program:
#include<stdio.h>
int main()
{
int n;
printf("Enter n value: ");
scanf("%d", &n);
int sum = n*(n+1)*(2*n+1)/6;
printf("Sum of squares of first %d natural numbers = %d", n, sum);
return 0;
}
Output:
Enter n value: 5
Sum of squares of first 5 natural numbers = 55
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