Sum of series in C language 1 + 1/(2*2) + 1/(3*3) + 1/(4*4) + ….. + 1/(n*n) using pow() Function

Learn about Sum of series in C language 1 + 1/(2*2) + 1/(3*3) + 1/(4*4) + ….. + 1/(n*n) using pow() Function in the below code example. Also refer the comments in the code snippet to get a detailed view about what’s actually happening.

Contents

Sum of series in C language 1 + 1/(22) + 1/(33) + 1/(44) + ….. + 1/(nn) using pow() Function

The below program finds the value of the given series,

1 + 1/(2*2) + 1/(3*3) + 1/(4*4) + ….. + 1/(n*n)

Program:

#include<stdio.h>
#include<math.h>
int main()
{
     int n, i=1;
     float sum=0.0;

     printf("Enter the limit (n Value): ");
     scanf("%d",&n);

     while(i<=n)
     {
         sum+=(1.0/pow(i,2)); //sum = sum + 1.0/ pow(i,2)
         i++;
     }

     printf("Sum = %f", sum);

     return 0;
}

Output:

Enter the limit (n Value): 5
Sum = 1.463611

Hope above code works for you and Refer the below Related Codes to gain more insights. Happy coding and come back again.