Sum of N elements in C using Pointer Using calloc() and free()

Learn about Sum of N elements in C using Pointer Using calloc() and free() in the below code example. Also refer the comments in the code snippet to get a detailed view about what’s actually happening.

Sum of N elements in C using Pointer Using calloc() and free()

Here, we have to allocate numbers using dynamic allocation i.e., Pointers. In below code, calloc() and free() functions are used.

#include<stdio.h>
#include<stdlib.h>
int main()
{
   int num, i, *ptr, sum=0;

   printf("Enter total number of elements(1 to 100): ");
   scanf("%d",&num);

   // memory allocated using malloc()
   ptr= (int*) calloc (num, sizeof(int));

   if(ptr==NULL)
   {
      printf("Memory not allocated.");
      return EXIT_FAILURE;
   }

   printf("Enter elements :\n");

   for(i=0;i<num;i++)
   {
      scanf("%d",ptr+i);
      sum += *(ptr+i);
   }

   printf("Sum= %d",sum);
   free(ptr);

   return 0;
}

Output:

Enter number of elements(1 to 100): 5
Enter elements :
4
5
3
7
8
Sum= 27

Hope above code works for you and Refer the below Related Codes to gain more insights. Happy coding and come back again.