How to pass a function as a parameter

For passing a function as a parameter, we are using a parameter s to be a pointer *s to the function similargeeks and that returns void type. so whenever we declare a pointer as a parameter to that array values are given to it as pointer.

#include <stdio.h>
void print(int n)  
{
    printf("%d ", n);
}
void similargeeks(void (*s)(int))  
{
    for(int i = 0; i < 5; i++) 
    {
        (*s)(i);
    }
}
int main(void)  
{
    similargeeks(print);
    return 0;
}

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In above example , similargeeks is declared with parameters with pointer and another function print is declared . similargeeks(print) ,by calling it acts as a pointer to print function.

Hope above code works for you and Refer the below Related Codes to gain more insights. Happy coding and come back again.

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