Check Leap Year Using nested if-else

Learn about Check Leap Year Using nested if-else in the below code example. Also refer the comments in the code snippet to get a detailed view about what’s actually happening.

Check Leap Year Using nested if-else

If a year is said to be leap year then it should meet some conditions. The below program uses nested if-else conditions to test the conditions and prints the result.

Program:

#include<stdio.h>
int main()
{
   int year;

   printf("Enter Year:");
   scanf("%d",&year);

   if(year%4==0)
   {
     if(year%100==0)
     {
       if(year%400==0)
         printf("%d is leap year.",year);

       else
         printf("%d is not leap year.",year);
     }

     else
       printf("%d is leap year.",year);
   }

   else
     printf("%d is not leap year.",year);

   return 0;
}

Output:

Enter Year: 2016
Leap Year.

Hope above code works for you and Refer the below Related Codes to gain more insights. Happy coding and come back again.