C program to print full diamond of numbers with Zeros

Learn about C program to print full diamond of numbers, starting with zero and ending with zero in the below code example. Also refer the comments in the code snippet to get a detailed view about what’s actually happening.

Contents

C program to print full diamond of numbers, starting with zero and ending with zero

      0
     010
    01210
   0123210
  012343210
 01234543210
0123456543210
 01234543210
  012343210
   0123210
    01210
     010
      0

Program:

#include<stdio.h> 
int main()
{
   int n, a=0;

   printf("Enter value of n: ");
   scanf("%d",&n);


   for(int i=1; i<=n+1; i++)
   {

     for(int j=i; j<=n; j++)
     {
       printf(" ");
     }


     for(int k=1; k<=2*i-1; k++)
     {
        if(k<i) printf("%d",a++);
        else if(k==i) printf("%d",a);
        else printf("%d",--a);
      }


      printf("\n");
   }


   for(int i=n; i>=1; i--)
   {
     for(int j=n; j>=i; j--)
     {
       printf(" ");
     }

     for(int k=1; k<=2*i-1; k++)
     {
       if(k<i) printf("%d",a++);
       else if(k==i) printf("%d",a);
       else printf("%d",--a);
     }
     printf("\n");
   }

   return 0;
}

Output:

Enter value of n: 6
      0
     010
    01210
   0123210
  012343210
 01234543210
0123456543210
 01234543210
  012343210
   0123210
    01210
     010
      0

Hope above code works for you and Refer the below Related Codes to gain more insights. Happy coding and come back again.