C Program to Find Neon Number in a Given Range

Learn about C Program to Find Neon Number in a Given Range in the below code example. Also refer the comments in the code snippet to get a detailed view about what’s actually happening.

Contents

C Program to Find Neon Number in a Given Range

Program:

#include<stdio.h>
int main()
{
    int m, n, i, sqr, j, sum;

    printf("Enter The Range m and n Value(m<n): ");
    scanf("%d %d",&m,&n);

    printf("Neon Number from %d to %d are:\n",m,n);

    for(i=m;i<=n;i++)
    {
       sum = 0;
       sqr = i*i;

       for( j=sqr ;j>0 ;j/=10 )
       {
           sum += (j%10);
       }

       if(sum == i)
       printf("%d\t",i);
    }

    return 0;
}

Output:

Enter The Range m and n Value(m<n): 1 100
Neon Number from 1 to 100 are:
1 9

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